Lab Cycle 3 - C++ - CodeAriyoo

Question 03 of 03

Armstrong Number and Reverse of a Number using While Loop

Problem Statement

Write a Turbo C++ program to input an integer number, reverse its digits using a while loop, and check whether the original number is an Armstrong number (sum of cubes of its digits equals the number).

C++

#include <iostream.h>
#include <conio.h>

void main() {
    int num, temp, digit, reverse = 0, sumOfCubes = 0;

    clrscr();

    cout << "Enter an integer number: ";
    cin >> num;

    temp = num;

    while (temp > 0) {
        digit = temp % 10;
        reverse = (reverse * 10) + digit;
        sumOfCubes = sumOfCubes + (digit * digit * digit);
        temp = temp / 10;
    }

    cout << "\n--- Results ---" << endl;
    cout << "Original Number : " << num << endl;
    cout << "Reversed Number : " << reverse << endl;

    if (sumOfCubes == num) {
        cout << num << " is an ARMSTRONG NUMBER (Sum of cubes: " << sumOfCubes << ")" << endl;
    } else {
        cout << num << " is NOT an Armstrong number (Sum of cubes: " << sumOfCubes << ")" << endl;
    }

    getch();
}

Code Segment	Explanation & Purpose
`temp = num;`	Preserves original number in a temporary variable for comparison after loop finishes.
`while (temp > 0)`	Repeats as long as there are remaining digits to process.
`digit = temp % 10;`	Extracts the rightmost digit using modulo 10.
`reverse = (reverse * 10) + digit;`	Shifts existing reversed number left by base 10 and adds the extracted digit.
`sumOfCubes += (digit * digit * digit);`	Computes cube of digit and accumulates into total sum.
`temp = temp / 10;`	Removes the processed rightmost digit.
`getch();`	Holds the output screen.

Question 3 of 3

Control Structures, Decision Making & Loops

Armstrong Number and Reverse of a Number using While Loop